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12x^2-3=53-2x^2
We move all terms to the left:
12x^2-3-(53-2x^2)=0
We get rid of parentheses
12x^2+2x^2-53-3=0
We add all the numbers together, and all the variables
14x^2-56=0
a = 14; b = 0; c = -56;
Δ = b2-4ac
Δ = 02-4·14·(-56)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*14}=\frac{-56}{28} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*14}=\frac{56}{28} =2 $
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